Laser Videodisc

A videodisc revolves at 1800 rpm beneath a laser read-out head. If the beam is 17 cm from the center of the di?

A videodisc revolves at 1800 rpm beneath a laser read-out head. If the beam is 17 cm from the center of the disc, how many meters of data pass beneath it in 0.11 s? Please provide an answer along with an explanation.

The disc is turning at 1800 rpm. First convert this to revolutions per second.
1800 rpm / (60 s/min) = 30 rev/s

Then calculate the speed of the disc at a radius of 0.17m:
Circumference = 2 * pi * r = 2 * pi * 0.17 m = 1.07 m
Speed = 30 rev/s * 1.07 m/rev = 32.0 m/s

Now calculate the distance in 0.11 s:
D = r*t = 32 m/s * 0.11s = 3.5 m

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